 # Question: How Many Address Lines 16mb Memory?

## How many address lines are required for 1mb memory?

20“20” address lines or address bus are required to span “1MB” memory space.

Because 1MB is equal to bytes..

## How is memory capacity calculated?

In your example for Range 1, you are correct. That is the size of the memory, stated in hexidecimal, in bytes. You may gain the most insight by first converting 00FF FFFF to a decimal number, then converting that number of bytes into megabytes. 1 MB = 1 Megabyte = 1024 * 1 KB = 1,048,576 bytes.

## How many address lines of the 8085 microprocessor are required to address 1024 memory locations?

Let us assume that we have a RAM chip of 2K x 8, It signifies that, we have 2 x 1024 = 2048 memory locations having information of 8 bits at each location. For selecting one of 2K = 211 memory locations in chip, there should be exactly input pins of 11 address lines.

## What is the size of memory address?

As I mentioned before, it’s the size of a machine word. Machine word is the amount of memory CPU uses to hold numbers (in RAM, cache or internal registers). 32-bit CPU uses 32 bits (4 bytes) to hold numbers. Memory addresses are numbers too, so on a 32-bit CPU the memory address consists of 32 bits.

## How many separate address and data lines are needed for a memory of 8k 16?

8K∗16=213∗16, thus 13 address lines and 16 data lines.

## How many address lines and data lines are required to provide a memory capacity of 16kx16?

How many address lines and data lines are required to provide a memory capacity of 16K×16? Answer will be 14,4.

## How many address lines are needed for memory?

Address lines needed to address each memory location – Example – Networking. It means that a memory of 2048 words, where each word is 4 bits. So to address 2048 (or 2K, where K means 2^10 or 1024), you need 11 bits, so 11 address lines.

## How do I calculate the number of address lines?

They specify which address to access in the memory. So the task is to find out how many bits are required to pass the input number as an address. In your example, the input is 2 kilobytes = 2048 = 2^11, hence the answer 11. If your input is 64 kilobytes, the answer is 16 (65536 = 2^16).

## What is the highest address in a 48k memory?

2 AnswersA) In a 48K memory Number of bits required is =log(48 * 1024)=16 bit.Now this 16 bit can represent highest address as (2^16)-1 =65535.But since the memory is only 48K it will represent highest address as (48*1024)-1=49151 (since one of the address will be 0)

## How many address lines are required for a 2k memory?

11 address linesIt is 2k in size. 11 address lines are needed to address all the addresses inside the EPROM. A similar calculation reveals that the 2K RAM also needs 11 address lines. The PIO chip only has 4 bytes inside, so it only needs 2 address lines.

## What is address line and data line?

The Bus (2) Buses consist of data lines, control lines, and address lines. While the data lines convey bits from one device to another, control lines determine the direction of data flow, and when each device can access the bus. Address lines determine the location of the source or destination of the data.

## How many address lines are needed for the memory unit 2m * 16?

→ it means 20 address lines and 16 data lines. therefore, general formula to find out ROM memory size is 2^m * n, where m is address lines and n is data lines. How many bits of memory does a RAM chip set with 12 address pins and 8 data pins have?

## How many address lines are required to represent 32k memory?

Ans. 32K = 25 x 210 = 215, Hence 15 address bits are needed; Only 16 bits can address this.

## How many address lines are used in 4k memory?

12 address lines10–1k; 11–2k; 12 address lines are require for 4k memory.

## How do I know my DDR memory size?

Determining a Memory Module’s Size and FeaturesMT = Micron Technologies (the memory chip maker)46 = DDR SDRAM.V = 2.5V DC.64M8 = 8 million rows x 8 (equals 64) x 8 banks (often written as 64 Meg x 8)TG = 66-pin TSOP chip package.–75 = 7.5ns @ CL2 latency (DDR 266)

## How do I find my memory address range?

The first address of memory 1 is 2000h = 8192. Memory 2 starts at 3000h, or 0011 0000 0000 0000 etc. So you can see that the binary digits in the 13th, 14th and 15th positions correspond to the starting addresses of the 4 memories: 0010 = memory 1, 0011 = memory 2, 0100 = memory 3 and 0101 = memory 4.